通过链式操作简化变换矩阵的创建
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Aspose.3D for Python via .NET API 提供了
TransformBuilder 类，它通过链操作简化了变换矩阵的创建。
假设有一个 TransformBuilder 实例结核病,以及连锁经营:
Python
import aspose.threed as a3d
# Change the (x, y, z) into (x + 1, y, z)
tb = a3d.utilities.TransformBuilder(a3d.utilities.ComposeOrder.APPEND)
a = tb.translate(1, 0, 0)
# Rotate alone with the Y axis with 180 deg will change the (x, y, z) into (-x, y, -z)
.rotate_euler_degree(0, 180, 0)
# Scale by 2 will change the (x, y, z) into (2x, 2y, 2z)
.scale(2)
# change the (x, y, z) into (z, y, x)
.rearrange(a3d.Axis.Z_AXIS, a3d.Axis.Y_AXIS, a3d.Axis.X_AXIS)
.matrix
如果此实例的合成顺序为Prepend，则从左到右计算最终矩阵，这意味着最终转换矩阵将执行以下任务:
- 将 (x，y，z) 改为 (x 1，y，z)
- 以180度的y轴单独旋转会将 (x，Y，z) 变为 (-x，y，-z)
- 缩放2将把 (x，y，z) 变成 (2x，2y，2z)
- 将 (x，y，z) 改为 (z，y，x)
但是，如果附加了撰写顺序，则顺序将反转，例如:
- 将 (x，y，z) 改为 (z，y，x)
- 缩放2将把 (x，y，z) 变成 (2x，2y，2z)
- 以180度的y轴单独旋转会将 (x，Y，z) 变为 (-x，y，-z)
- 将 (x，y，z) 改为 (x 1，y，z)
Python
import aspose.threed as a3d
# use prepend order so the calculation is performed from left to right:
m = (a3d.utilities.TransformBuilder(a3d.utilities.ComposeOrder.PREPEND))
# Change the (x, y, z) into (x + 1, y, z)
.translate(1, 0, 0)
# Rotate alone with the Y axis with 180deg will change the (x, y, z) into (-x, y, -z)
.rotate_euler_degree(0, 180, 0)
# Scale by 2 will change the (x, y, z) into (2x, 2y, 2z)
.scale(2)
# change the (x, y, z) into (z, y, x)
.rearrange(a3d.Axis.Z_AXIS, a3d.Axis.Y_AXIS, a3d.Axis.X_AXIS)
.matrix
# Apply this matrix on a (0, 0, 0) vector, then we get the right result (0, 0, -2)
t = m * a3d.utilities.Vector3.ORIGIN;