用C++判断Shape是否为Smart Art Shape

可能的使用场景

智能图形是Microsoft Excel中特殊的形状，允许您自动生成复杂的图表。使用Shape.IsSmartArt属性可以确定该形状是智能图形还是常规图形。

确定形状是否为智能图形

以下示例代码加载包含智能图形的sample Excel文件，如下图所示。然后打印第一个形状的Shape.IsSmartArt属性的值。请参阅下面提供的示例代码的控制台输出。

示例代码

#include <iostream>
#include "Aspose.Cells.h"

using namespace Aspose::Cells;
using namespace Aspose::Cells::Drawing;

int main()
{
    Aspose::Cells::Startup();

    // Load the sample smart art shape - Excel file
    U16String inputFilePath(u"sampleSmartArtShape.xlsx");
    Workbook wb(inputFilePath);

    // Access first worksheet
    WorksheetCollection sheets = wb.GetWorksheets();
    Worksheet ws = sheets.Get(0);

    // Access first shape
    ShapeCollection shapes = ws.GetShapes();
    Shape sh = shapes.Get(0);

    // Determine if shape is smart art
    std::cout << "Is Smart Art Shape: " << sh.IsSmartArt() << std::endl;

    Aspose::Cells::Cleanup();
}

控制台输出

Is Smart Art Shape: True